Plot Scalars Over a Circular Arc

Interpolate the scalars of a dataset over a circular arc.

# sphinx_gallery_thumbnail_number = 2
import pyvista as pv
from pyvista import examples

Volumetric Mesh

Add the height scalars to a uniform 3D mesh.

mesh = examples.load_uniform()
mesh['height'] = mesh.points[:, 2]

# Make two points at the bounds of the mesh and one at the center to
# construct a circular arc.
normal = [0, 1, 0]
polar = [mesh.bounds[0], mesh.bounds[2], mesh.bounds[5]]
center = [mesh.bounds[0], mesh.bounds[2], mesh.bounds[4]]
angle = 90.0

# Preview how this circular arc intersects this mesh
arc = pv.CircularArcFromNormal(center, 100, normal, polar, angle)

p = pv.Plotter()
p.add_mesh(mesh, style="wireframe", color="w")
p.add_mesh(arc, color="b")
a = arc.points[0]
b = arc.points[-1]
p.add_point_labels(
    [a, b], ["A", "B"], font_size=48, point_color="red", text_color="red"
)
p.show()

Out:

[(21.886664873203234, 21.886664873203234, 21.886664873203234),
 (4.5, 4.5, 4.5),
 (0.0, 0.0, 1.0)]

Run the filter and produce a line plot.

mesh.plot_over_circular_arc_normal(center, 100, normal, polar, angle, 'height')